Question

how many unique gametes could be produced through independent assortment by an individual with the genotype aabbccddee?

Explanation:

Step1: Determine the number of heterozygous gene pairs

The genotype is \(AaBbCCDdEE\). The heterozygous gene pairs are \(Aa\), \(Bb\), \(Dd\) (since \(CC\) and \(EE\) are homozygous). So \(n = 3\) (where \(n\) is the number of heterozygous gene pairs).

Step2: Use the formula for the number of gametes

The formula for the number of unique gametes produced through independent assortment is \(2^{n}\). Substitute \(n = 3\) into the formula: \(2^{3}=8\).

Answer:

8