Question

having problems staying logged in or are you experiencing issues? please visit our troubleshooting section for solutions. an object has an acceleration of 12.0 m/s/s. if the net force acting upon this object were one - third of the original net force, then its new acceleration would be ______ m/s/s. enter your answer directly into the field or use our built - in number pad. new acceleration (in m/s/s) check answer student name: lr@ss.w**s.nt level: wizard progress report tap for question - specific help help me! view directions to main menu

Explanation:

Step1: Use Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. Initially, \(F_1=m\times a_1\), given \(a_1 = 12.0\space m/s^2\).

Step2: Analyze the new - force situation

The new force \(F_2=\frac{1}{3}F_1\). Since \(F_2 = m\times a_2\) and \(F_1=m\times a_1\), substituting \(F_2=\frac{1}{3}F_1\) into \(F_2 = m\times a_2\) gives \(\frac{1}{3}F_1=m\times a_2\). But \(F_1=m\times a_1\), so \(\frac{1}{3}(m\times a_1)=m\times a_2\).

Step3: Solve for the new acceleration

Cancel out the mass \(m\) (assuming the mass of the object remains constant) from both sides of the equation \(\frac{1}{3}(m\times a_1)=m\times a_2\). We get \(a_2=\frac{1}{3}a_1\). Substitute \(a_1 = 12.0\space m/s^2\) into the formula, then \(a_2=\frac{1}{3}\times12.0\space m/s^2\).

Answer:

\(4.0\)