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Question
- in guinea pigs, short fur (s) is dominant to long fur (s). two heterozygous guinea pigs (ss) mate. complete the punnett square and then list the percentages of the expected genotypes for their offspring. heterozygous guinea pig heterozygous guinea pig genotype probability (%) homozygous dominant heterozygous homozygous recessive
Step1: Create Punnett square
Parents are \( Ss\times Ss \).
| S | s | |
|---|---|---|
| s | \( Ss \) | \( ss \) |
Step2: Calculate genotype percentages
- For \( SS \) (homozygous dominant): \( \frac{1}{4}= 25\% \)
- For \( Ss \) (heterozygous): \( \frac{2}{4}=50\% \)
- For \( ss \) (homozygous recessive): \( \frac{1}{4} = 25\% \)
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- Homozygous dominant: \( 25\% \)
- Heterozygous: \( 50\% \)
- Homozygous recessive: \( 25\% \)