Question

graph the function.
$f(x)=3\sqrt{x}+2$
plot four points on the graph of the function: the left - most point and three additional points. then click on the graph - a - function button.

Explanation:

Step1: Find the left - most point

The domain of $y = 3\sqrt{x}+2$ is $x\geq0$. When $x = 0$, $y=3\sqrt{0}+2=2$. So the left - most point is $(0,2)$.

Step2: Find additional points

Let $x = 1$, then $y=3\sqrt{1}+2=3 + 2=5$. So the point is $(1,5)$.

Step3: Another additional point

Let $x = 4$, then $y=3\sqrt{4}+2=3\times2 + 2=8$. So the point is $(4,8)$.

Step4: One more additional point

Let $x = 9$, then $y=3\sqrt{9}+2=3\times3+2 = 11$. So the point is $(9,11)$.

Answer:

The four points are $(0,2),(1,5),(4,8),(9,11)$