given $(x - 7)^2 = 36$, select the values of $x$.

$x = 13$
$x = 1$
$x = -29$
$x = 42$

Question

given $(x - 7)^2 = 36$, select the values of $x$.

$x = 13$
  $x = 1$
  $x = -29$
  $x = 42$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Solving Quadratic Equations" ], "new_concepts": [], "current_concepts": [ "Solving Quadratic Equations" ] } ## Take the square root of both sides $$ \begin{aligned} (x - 7)^2 &= 36 \ x - 7 &= \pm\sqrt{36} \ x - 7 &= \pm 6 \end{aligned} $$ ## Solve for the two possible values of x $$ \begin{aligned} x_1 &= 7 + 6 = 13 \ x_2 &= 7 - 6 = 1 \end{aligned} $$

(A) $x = 13$

(B) $x = 1$

(C) $x = -29$

(D) $x = 42$

{ "subject": "Mathematics", "question_type": "Multiple Choice", "knowledge_point": [ "Mathematics", "Algebra", "Solving Quadratic Equations" ] }

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Take the square root of both sides

Solve for the two possible values of x

Answer: