Question

formula: pe = mgh g= 9.8 m/s²

1. find the gravitational potential energy of a light that has a mass of 13.0 kg and is 4.8 m above the ground.

Explanation:

Step1: Substitute the values into the formula

Given \(m = 13.0\space kg\), \(g=9.8\space m/s^{2}\), \(h = 4.8\space m\), and the formula \(PE=mgh\).
Substitute these values: \(PE=(13.0)(9.8)(4.8)\)

Step2: Calculate the product

First, calculate \(13.0\times9.8 = 127.4\)
Then, \(127.4\times4.8=611.52\)

Answer:

\(611.52\space J\)