Question

1. a force of 6.0 n is needed to push a sled 15 m. calculate the amount of work done
2. a simple machine uses a force of 28 n force to move an object 3.0 m. calculate the

amount of work done.

1. a force of 10 n was used to lift an object to a height of 5.0 m. calculate the amount of work

done.

1. a force of 3.0 n was used to move a barrel up an inclined plane. it was determined that 24

j of work was done. calculate the distance the barrel moved.

Explanation:

Step1: Recall the formula for work

The formula for work \(W\) is \(W = F\times d\), where \(F\) is the force and \(d\) is the distance.

Step2: Solve for each problem

Problem 1

Given \(F = 6.0\space N\) and \(d=15\space m\).
Substitute into the formula: \(W = 6.0\times15\).
\(W=90\space J\)

Problem 2

Given \(F = 28\space N\) and \(d = 3.0\space m\).
Substitute into the formula: \(W=28\times3.0\).
\(W = 84\space J\)

Problem 3

Given \(F = 10\space N\) and \(d = 5.0\space m\).
Substitute into the formula: \(W=10\times5.0\).
\(W=50\space J\)

Problem 4

Given \(W = 24\space J\) and \(F = 3.0\space N\).
Rearrange the formula \(W = F\times d\) to \(d=\frac{W}{F}\).
Substitute the values: \(d=\frac{24}{3.0}\).
\(d = 8.0\space m\)

Answer:

1. \(90\space J\)
2. \(84\space J\)
3. \(50\space J\)
4. \(8.0\space m\)