Question

1. a force of 18 n compresses a spring 0.06 m. what is the spring constant?

Explanation:

Step1: Recall Hooke's Law

Hooke's Law states that the force \( F \) exerted on a spring is given by \( F = kx \), where \( k \) is the spring constant and \( x \) is the displacement from the equilibrium position. We need to solve for \( k \), so we can rearrange the formula to \( k=\frac{F}{x} \).

Step2: Substitute the given values

We are given that \( F = 18\space N \) and \( x = 0.06\space m \). Substituting these values into the formula for \( k \), we get \( k=\frac{18}{0.06} \).

Step3: Calculate the value of \( k \)

Performing the division \( \frac{18}{0.06}=300 \). So the spring constant \( k \) is \( 300\space N/m \).

Answer:

The spring constant is \( \boldsymbol{300\space N/m} \).