Question

find the quotient.

\\\frac{-6x^3 + 3x^2 - 8x}{x}\\

\\?x^2 + \quadx + \quad\\

Explanation:

Set up the division expression

$$ \frac{-6x^3 + 3x^2 - 8x}{x} $$

Divide each term by the monomial

$$ \frac{-6x^3}{x} + \frac{3x^2}{x} - \frac{8x}{x} $$

Simplify each term

$$ -6x^2 + 3x - 8 $$

Answer:

Find the quotient.

$$\frac{-6x^3 + 3x^2 - 8x}{x}$$

<blank>-6</blank>\(x^2 +\) <blank>3</blank>\(x +\) <blank>-8</blank>