Question

find the missing number so that the equation has no solutions.\\(x + 16 + \square x = 4x + 3\\)

Explanation:

Step1: Let missing number be $a$

Rewrite equation: $x + 16 + ax = 4x + 3$

Step2: Combine like terms (x terms)

$(1+a)x + 16 = 4x + 3$

Step3: Set x coefficients equal

For no solution: $1+a = 4$
Solve: $a = 4 - 1 = 3$

Step4: Verify constant terms

With $a=3$, equation becomes $4x + 16 = 4x + 3$. Subtract $4x$: $16=3$, which is false.

Answer:

3