Question

find the measure of $overline{ad}$. assume that the given figure is not drawn to scale.
$2\frac{3}{8}$ in.
$2\frac{1}{4}$ in.
a
c
d
a) $4\frac{5}{8}$ in.
b) $3\frac{5}{8}$ in.
c) $4\frac{1}{5}$ in.
d) $2\frac{1}{5}$ in.

Explanation:

Step1: Convert mixed - numbers to improper fractions

$2\frac{3}{8}=\frac{2\times8 + 3}{8}=\frac{19}{8}$ and $2\frac{1}{4}=\frac{2\times4+1}{4}=\frac{9}{4}=\frac{18}{8}$

Step2: Add the lengths of AC and CD

$AD=AC + CD$. So $AD=\frac{19}{8}+\frac{18}{8}=\frac{19 + 18}{8}=\frac{37}{8}$

Step3: Convert the improper fraction back to a mixed - number

$\frac{37}{8}=4\frac{5}{8}$

Answer:

A. $4\frac{5}{8}$ in.