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find the inverse of $f(x) = 3x + 9$. 1. $y = 3x - 3$ 2. $y = -3x - 9$ 3…

Question

find the inverse of $f(x) = 3x + 9$.

  1. $y = 3x - 3$
  2. $y = -3x - 9$
  3. $y = \frac{x}{3} - 3$
  4. $y = \frac{x + 9}{3}$

Explanation:

Step1: Replace $f(x)$ with $y$

$y = 3x +9$

Step2: Swap $x$ and $y$

$x = 3y +9$

Step3: Isolate $y$

Subtract 9 from both sides: $x-9 = 3y$
Divide by 3: $y=\frac{x-9}{3}=\frac{x}{3}-3$

Answer:

  1. $y=\frac{x}{3}-3$