Question

find the exact value of cos g in simplest radical form.
triangle with vertices g, h (right angle), i; gh = 4, hi = √13, gi = √29
answer attempt 1 out of 2
cos g = blank
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Explanation:

Step1: Recall cosine definition

In a right triangle, $\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}$. For $\angle G$, adjacent side is $GH = 4$, hypotenuse is $GI=\sqrt{29}$.

Step2: Apply cosine formula

$\cos G=\frac{GH}{GI}=\frac{4}{\sqrt{29}}$. Rationalize the denominator: $\frac{4\sqrt{29}}{29}$.

Answer:

$\frac{4\sqrt{29}}{29}$