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find the equation of a line parallel to y = -x - 5 that passes through …

Question

find the equation of a line parallel to y = -x - 5 that passes through the point (6,9). answer y - 9 = -(x - 6) y + 9 = x + 6 y + 9 = -(x + 6) y - 9 = x - 6

Explanation:

Step1: Determine the slope of the new line

Parallel lines have equal slopes. The slope of the line $y=-x - 5$ is $m=-1$. So the slope of the line we want to find is also $m=-1$.

Step2: Use the point - slope form of a line equation

The point - slope form is $y - y_1=m(x - x_1)$, where $(x_1,y_1)=(6,9)$ and $m=-1$. Substituting these values, we get $y - 9=-1(x - 6)$ or $y - 9=-(x - 6)$.

Answer:

A. $y - 9=-(x - 6)$