factor the trinomial completely. $x^{2}+x - 30$ $x^{2}+x - 30=\\square$

$factor the trinomial completely. $x^{2}+x - 30$ $x^{2}+x - 30=\\square$$

factor the trinomial completely.
$x^{2}+x - 30$
$x^{2}+x - 30=\square$

We need two numbers that multiply to $-30$ and add to $1$. The numbers are $6$ and $-5$, since $6 \times (-5) = -30$ and $6 + (-5) = 1$.

Substitute the pair into the binomial factors of the form $(x + a)(x + b)$.

$(x + 6)(x - 5)$