Question

factor the polynomial by grouping.\\(9x^2 - 9x - x + 1\\)\
a \\((x - 1)(9x + 1)\\)\
b \\((x - 1)(9x - 1)\\)\
c \\((x + 1)(9x - 1)\\)\
d \\((x + 1)(9x + 1)\\)

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(9x^2 - 9x) + (-x + 1)$

Step2: Factor out GCF from each group

Factor out $9x$ from the first group: $9x(x - 1)$, and factor out $-1$ from the second group: $-1(x - 1)$

Step3: Factor out the common binomial factor

Now we have $9x(x - 1) - 1(x - 1)$, factor out $(x - 1)$: $(x - 1)(9x - 1)$

Answer:

B. $(x - 1)(9x - 1)$