Question

factor the polynomial by grouping. 8st + 12t - 2s - 3 8st + 12t - 2s - 3 = (factor completely.)

Explanation:

Step1: Group the terms

$(8st + 12t)+(-2s - 3)$

Step2: Factor out the GCF from each group

$4t(2s + 3)-1(2s + 3)$

Step3: Factor out the common binomial factor

$(2s + 3)(4t-1)$

Answer:

$(2s + 3)(4t - 1)$