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factor completely. $16j^2 - 25$

Question

factor completely.
$16j^2 - 25$

Explanation:

Step1: Identify as difference of squares

The expression \(16j^2 - 25\) is a difference of squares, since \(16j^2=(4j)^2\) and \(25 = 5^2\). The formula for factoring a difference of squares is \(a^2 - b^2=(a + b)(a - b)\).

Step2: Apply the difference of squares formula

Let \(a = 4j\) and \(b = 5\). Substituting into the formula, we get \((4j + 5)(4j - 5)\).

Answer:

\((4j + 5)(4j - 5)\)