Question

factor completely. $18f^{3}+4f^{2}+9f + 2$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(18f^3 + 4f^2) + (9f + 2)$

Step2: Factor out GCF from each group

Factor out $2f^2$ from the first group and $1$ from the second group: $2f^2(9f + 2) + 1(9f + 2)$

Step3: Factor out the common binomial factor

Factor out $(9f + 2)$: $(2f^2 + 1)(9f + 2)$

Answer:

$(2f^2 + 1)(9f + 2)$