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factor completely. $8m^3 - 16m^2 + m - 2$

Question

factor completely.
$8m^3 - 16m^2 + m - 2$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(8m^3 - 16m^2) + (m - 2)$

Step2: Factor out GCF from each group

Factor out $8m^2$ from the first group and $1$ from the second group: $8m^2(m - 2) + 1(m - 2)$

Step3: Factor out the common binomial factor

Factor out $(m - 2)$ from both terms: $(m - 2)(8m^2 + 1)$

Answer:

$(m - 2)(8m^2 + 1)$