Question

express the following in simplest a + bi form. $sqrt{9}+sqrt{-36}$ -9i 3 - 6i 9i 3 + 6i done

Explanation:

Step1: Simplify square - root of 9

The square - root of 9 is 3 since $3\times3 = 9$, so $\sqrt{9}=3$.

Step2: Simplify square - root of - 36

We know that $\sqrt{-1}=i$. Then $\sqrt{-36}=\sqrt{36\times(-1)}=\sqrt{36}\times\sqrt{-1}=6i$.

Step3: Combine the results

$\sqrt{9}+\sqrt{-36}=3 + 6i$.

Answer:

D. $3 + 6i$