QUESTION IMAGE
Question
examine the system of equations.
x + 3y = 7,
2x + 4y = 9
which variable would be the most efficient to solve for?
○ x in the first equation
○ y in the first equation
○ x in the second equation
○ y in the second equation
Step1: Analyze the first equation
The first equation is \(x + 3y = 7\). To solve for \(x\), we can simply subtract \(3y\) from both sides: \(x = 7 - 3y\). This is a straightforward operation with a coefficient of 1 for \(x\).
Step2: Analyze solving for \(y\) in the first equation
To solve for \(y\) in \(x + 3y = 7\), we would need to subtract \(x\) and then divide by 3: \(y=\frac{7 - x}{3}\), which involves more operations.
Step3: Analyze the second equation for \(x\)
The second equation is \(2x + 4y = 9\). Solving for \(x\) would require subtracting \(4y\) and then dividing by 2: \(x=\frac{9 - 4y}{2}\), more steps than solving for \(x\) in the first equation.
Step4: Analyze the second equation for \(y\)
Solving for \(y\) in \(2x + 4y = 9\) would involve subtracting \(2x\) and dividing by 4: \(y=\frac{9 - 2x}{4}\), also more steps.
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A. \(x\) in the first equation