Question

evaluate the following.
click on
ot a real number\ if applicable.
$-sqrt{64} = \square$
$sqrt{-36} = \square$

Explanation:

Step1: Evaluate positive square root

$\sqrt{64}=8$

Step2: Apply negative sign

$-\sqrt{64}=-8$

Step3: Analyze square root of negative

$\sqrt{-36}$ has no real solution, since square roots of negative numbers are not real numbers.

Answer:

$-\sqrt{64} = -8$
$\sqrt{-36} = \text{Not a real number}$