Question

equilibrium review
started: dec 10 at 8:14pm
quiz instructions
you can complete this review up to 3 times. it will be worth 2.5 points extra credit onto the exam.
question 7
1 pts
a person has a mass of 125 kg. when they are at rest, standing on level ground, what must be the magnitude of the normal force that the ground exerts on them?

Explanation:

Step1: Recall the formula for weight

The weight \( W \) of an object is given by \( W = mg \), where \( m \) is the mass and \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^2 \)).

Step2: Identify the forces in equilibrium

When the person is at rest on level ground, the normal force \( F_N \) exerted by the ground is equal in magnitude to the weight of the person (since the net force is zero, forces are in equilibrium).

Step3: Calculate the weight (and thus the normal force)

Given \( m = 125 \, \text{kg} \) and \( g = 9.8 \, \text{m/s}^2 \), we calculate \( W = F_N = mg \).
Substituting the values: \( F_N = 125 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 1225 \, \text{N} \).

Answer:

\( 1225 \, \text{N} \)