Question

the equation of a linear function in point-slope form is $y - y_1 = m(x - x_1)$. harold correctly wrote the equation $y = 3(x - 7)$ using a point and the slope. which point did harold use?

• $(7, 3)$
• $(0, 7)$
• $(7, 0)$
• $(3, 7)$

Explanation:

Step1: Recall point - slope form

The point - slope form of a linear equation is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope.
We are given the equation $y = 3(x - 7)$. We can rewrite this equation in the form $y-y_1=m(x - x_1)$.
If we rewrite $y = 3(x - 7)$ as $y-0=3(x - 7)$, by comparing with $y - y_1=m(x - x_1)$, we can see that $m = 3$, $x_1=7$ and $y_1 = 0$.

Step2: Identify the point

So the point $(x_1,y_1)$ is $(7,0)$ since $x_1 = 7$ and $y_1=0$.

Answer:

(7, 0)