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at the end of a snow storm, suav saw there was a lot of snow on his fro…

Question

at the end of a snow storm, suav saw there was a lot of snow on his front lawn. the temperature increased and the snow began to melt at a steady rate. there was a depth of 16 inches of snow on the lawn when the storm ended and then it started melting at a rate of 2 inches per hour. make a table of values and then write an equation for s, in terms of t, representing the depth of snow on suav’s lawn, in inches, t hours after the snow stopped falling.

number of hours after the stormdepth of snow on suav’s lawn (inches)
1
2
3

Explanation:

Step1: Fill the table for t=0

At \( t = 0 \) (when the storm stopped), the depth of snow \( S = 16 \) inches. So the first row of the table is \( 0 \) and \( 16 \).

Step2: Fill the table for t=1

The snow melts at a rate of 2 inches per hour. So after 1 hour (\( t = 1 \)), the depth of snow is \( 16-2\times1 = 14 \) inches. So the second row is \( 1 \) and \( 14 \).

Step3: Fill the table for t=2

After 2 hours (\( t = 2 \)), the depth of snow is \( 16 - 2\times2=12 \) inches. So the third row is \( 2 \) and \( 12 \).

Step4: Fill the table for t=3

After 3 hours (\( t = 3 \)), the depth of snow is \( 16-2\times3 = 10 \) inches. So the fourth row is \( 3 \) and \( 10 \).

Step5: Write the equation for S in terms of t

The initial depth of snow is 16 inches (when \( t = 0 \)) and it decreases by 2 inches each hour. So the equation is a linear equation of the form \( S=S_0 - rt \), where \( S_0 = 16 \) (initial depth) and \( r = 2 \) (rate of melting). So \( S=16 - 2t \).

Table:

Number of Hours after the StormDepth of Snow on Suav’s Lawn (Inches)
114
212
310

Equation:

The equation representing the depth of snow \( S \) in terms of \( t \) hours is \( \boldsymbol{S = 16 - 2t} \)

Answer:

Step1: Fill the table for t=0

At \( t = 0 \) (when the storm stopped), the depth of snow \( S = 16 \) inches. So the first row of the table is \( 0 \) and \( 16 \).

Step2: Fill the table for t=1

The snow melts at a rate of 2 inches per hour. So after 1 hour (\( t = 1 \)), the depth of snow is \( 16-2\times1 = 14 \) inches. So the second row is \( 1 \) and \( 14 \).

Step3: Fill the table for t=2

After 2 hours (\( t = 2 \)), the depth of snow is \( 16 - 2\times2=12 \) inches. So the third row is \( 2 \) and \( 12 \).

Step4: Fill the table for t=3

After 3 hours (\( t = 3 \)), the depth of snow is \( 16-2\times3 = 10 \) inches. So the fourth row is \( 3 \) and \( 10 \).

Step5: Write the equation for S in terms of t

The initial depth of snow is 16 inches (when \( t = 0 \)) and it decreases by 2 inches each hour. So the equation is a linear equation of the form \( S=S_0 - rt \), where \( S_0 = 16 \) (initial depth) and \( r = 2 \) (rate of melting). So \( S=16 - 2t \).

Table:

Number of Hours after the StormDepth of Snow on Suav’s Lawn (Inches)
114
212
310

Equation:

The equation representing the depth of snow \( S \) in terms of \( t \) hours is \( \boldsymbol{S = 16 - 2t} \)