Question

an elephant of weight 45000n stands with all four feet on the floor. the average pressure on the floor due to the elephant foot in contact with it is 34000pa. what is the area of each foot of the elephant? o a. 1.3m² o b. 0.33m² o c. 0.19m² o d. 0.76m²

Explanation:

Step1: Recall the pressure formula

Pressure \( P=\frac{F}{A} \), where \( F \) is the force and \( A \) is the area. Here, \( F = 45000N \) and \( P=34000Pa \). We can rewrite the formula for area as \( A=\frac{F}{P} \).

Step2: Calculate the total area of the four feet

Substitute the values into the formula: \( A=\frac{45000}{34000}\approx1.32m^{2} \).

Step3: Calculate the area of each foot

Since there are four feet, the area of each foot \( a=\frac{A}{4} \). So \( a=\frac{1.32}{4}=0.33m^{2} \).

Answer:

B. \( 0.33m^{2} \)