Question

each particle in gas a and gas b has the same mass. the particles in gas a are moving at a higher average speed than the particles in gas b.
in which gas do the particles have the higher average kinetic energy?
gas a
gas b
neither; their particles have the same average kinetic energy
which has the higher gas pressure?
gas a
gas b
neither; their gas pressures are the same

Explanation:

Step1: Recall the formula for average kinetic energy

The formula for the average kinetic energy of a particle is \(K.E.=\frac{1}{2}mv^{2}\), where \(m\) is the mass and \(v\) is the speed. Since \(m\) is the same for gas A and gas B, and \(v_{A}>v_{B}\) (average speed of gas A particles > average speed of gas B particles), by the formula \(K.E.=\frac{1}{2}mv^{2}\), gas A has higher average kinetic energy.

Step2: Recall the relationship between particle speed and gas pressure

Gas pressure is related to the momentum transfer of gas particles when they collide with the walls of the container. The momentum of a particle is \(p = mv\). The force exerted on the wall during a collision (related to pressure) is proportional to the change in momentum per unit time. Since \(m\) is the same for gas A and gas B and \(v_{A}>v_{B}\), gas A particles have higher momentum. Assuming the number of particles per unit volume and the volume of the container (if relevant) are the same (not stated otherwise, we assume a fair comparison based on the given information of particle - level differences), gas A has higher pressure.

Answer:

For the average kinetic energy: gas A.
For the gas pressure: gas A.