Question

during the filming of an action movie, a stunt performer falls off the roof of a building from a height of 30 feet. she lands safely on a soft pad 6 feet above the ground. to the nearest tenth of a second, how long is the stunt performer in the air before landing on the pad? hint: use the formula h = -16t² + s.

Explanation:

Step1: Identificar valores de h y s

La altura inicial $s = 30$ pies y la altura final $h = 6$ pies. Sustituimos en la fórmula $h=-16t^{2}+s$.
$$6=-16t^{2}+30$$

Step2: Reorganizar la ecuación

Restamos 30 de ambos lados de la ecuación:
$$6 - 30=-16t^{2}$$
$$- 24=-16t^{2}$$

Step3: Resolver para $t^{2}$

Dividimos ambos lados por - 16:
$$t^{2}=\frac{-24}{-16}=\frac{3}{2}=1.5$$

Step4: Resolver para $t$

Tomamos la raíz cuadrada de ambos lados. Tomamos solo la solución positiva ya que $t$ representa tiempo.
$$t=\sqrt{1.5}\approx1.2$$

Answer:

$1.2$