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6. dna is approximately 2.5 nm in length. if an average man is 5 ft 10 …

Question

  1. dna is approximately 2.5 nm in length. if an average man is 5 ft 10 in. tall, how many dna molecules could be stacked to extend from the ground to the top of the head of an average man? 1m = 1000 mm 325000μm 1nm

Explanation:

Step1: Convert man's height to inches

1 foot = 12 inches. A man is 5 ft 10 in. So, \(5\times12 + 10=70\) inches.

Step2: Convert inches to meters

1 inch = 0.0254 m. So, \(70\times0.0254 = 1.778\) m.

Step3: Convert DNA length from nm to m

1 nm = \(1\times10^{-9}\) m. So, 2.5 nm = \(2.5\times10^{-9}\) m.

Step4: Calculate number of DNA molecules

Number of DNA molecules \(n=\frac{\text{man's height}}{\text{DNA length}}\). So, \(n=\frac{1.778}{2.5\times10^{-9}} = 7.112\times10^{8}\).

Answer:

\(7.112\times10^{8}\)