Question

6
directions: drag each picture to the correct location on the chart. pictures may be used more than once.
in pea plants, the allele that codes for purple flower color (b) is dominant to the allele that codes for white flower color (b). a scientist crosses a heterozygous purple flowered pea plant (bb) with a homozygous white flowered pea plant (bb).
the punnett square representing the scientist’s cross is shown below. drag and drop the picture that represents the phenotype that will be expressed for each potential genotype shown in the punnett square.
images of white and purple flowers
punnett square with b, b at top and b at left, empty cells below

Explanation:

Step1: Analyze Genotype 1 (Bb)

The first cell in the Punnett square (top - left, combining B from the heterozygous parent and b from the homozygous white parent) has the genotype Bb. Since B (purple) is dominant over b (white), the phenotype for Bb is purple. So we use the picture of the purple flower for this cell.

Step2: Analyze Genotype 2 (bb)

The second cell in the Punnett square (top - right, combining b from the heterozygous parent and b from the homozygous white parent) has the genotype bb. Since there is no dominant B allele, the phenotype is white. So we use the picture of the white flower for this cell.

Answer:

• For the cell with genotype Bb: Drag the picture of the purple flower (the blue - colored flower image) to this cell.
• For the cell with genotype bb: Drag the picture of the white flower (the white - colored flower image) to this cell.