Question

the data below shows the number of harp seals and brown bears in the world as of 2010. kaylee set up a ratio of the number of harp seals to the number of brown bears. continue her work to estimate how many times as many harp seals there were than brown bears in 2010. next, decompose the expression into two separate factors, one with the leading terms and the other with the powers of 10. species population harp seal 4.5×10^6 brown bear 1.86×10^5 harp seal / brown bear = (4.5×10^6)/(1.86×10^5)≈(5×10^6)/(2×10^5) = □/□×□/□ 2 10^5 10^6 5

Explanation:

Step1: Separate leading - terms and powers of 10

We have $\frac{5\times10^{6}}{2\times10^{5}}$. We can split this fraction into two parts: $\frac{5}{2}\times\frac{10^{6}}{10^{5}}$.

Step2: Calculate each part

For $\frac{5}{2}= 2.5$, and for $\frac{10^{6}}{10^{5}}$, using the rule $\frac{a^{m}}{a^{n}}=a^{m - n}$, we get $10^{6-5}=10^{1}=10$.

Step3: Multiply the results

$2.5\times10 = 25$.

Answer:

The number of harp seals was about 25 times the number of brown bears. The blanks should be filled as $\frac{5}{2}\times\frac{10^{6}}{10^{5}}$. So the values for the blanks (from left - to - right, top - to - bottom) are 5, 10⁶, 2, 10⁵.