Question

data analysis and post lab questions:

	a	b	c
initial mass (g)	3	3	3
final mass (g)	3	1	7
change in mass (final - initial)
percent change (use formula)
type of solution (hypertonic, hypotonic, isotonic)

(handwritten notes: \hypertonic\, \hypotonic\, \isotonic\, \water follows solutes\)

Explanation:

Step1: Calculate Change in Mass for Solution A

Initial mass = 3g, Final mass = 3g. Change in mass = final - initial = $3 - 3 = 0$g.

Step2: Calculate Percent Change for Solution A

Percent change formula: $\frac{\text{Change in Mass}}{\text{Initial Mass}} \times 100\%$. So, $\frac{0}{3} \times 100\% = 0\%$.

Step3: Determine Solution Type for A

Since change in mass is 0, it's isotonic (no net water movement).

Step4: Calculate Change in Mass for Solution B

Initial mass = 3g, Final mass = 1g. Change in mass = $1 - 3 = -2$g.

Step5: Calculate Percent Change for Solution B

$\frac{-2}{3} \times 100\% \approx -66.67\%$ (mass loss, water moved out, hypertonic solution).

Step6: Calculate Change in Mass for Solution C

Initial mass = 3g, Final mass = 7g. Change in mass = $7 - 3 = 4$g.

Step7: Calculate Percent Change for Solution C

$\frac{4}{3} \times 100\% \approx 133.33\%$ (mass gain, water moved in, hypotonic solution).

Filled Table (Rows: Change in Mass, Percent Change, Type of Solution):

Solution	Change in Mass (g)	Percent Change	Type of Solution
B	-2	≈ -66.67%	Hypertonic
C	4	≈ 133.33%	Hypotonic

(Note: If the question was to fill the table, this is the completed version. If specific values for a column were needed, extract accordingly.)

Answer:

Step1: Calculate Change in Mass for Solution A

Initial mass = 3g, Final mass = 3g. Change in mass = final - initial = $3 - 3 = 0$g.

Step2: Calculate Percent Change for Solution A

Percent change formula: $\frac{\text{Change in Mass}}{\text{Initial Mass}} \times 100\%$. So, $\frac{0}{3} \times 100\% = 0\%$.

Step3: Determine Solution Type for A

Since change in mass is 0, it's isotonic (no net water movement).

Step4: Calculate Change in Mass for Solution B

Initial mass = 3g, Final mass = 1g. Change in mass = $1 - 3 = -2$g.

Step5: Calculate Percent Change for Solution B

$\frac{-2}{3} \times 100\% \approx -66.67\%$ (mass loss, water moved out, hypertonic solution).

Step6: Calculate Change in Mass for Solution C

Initial mass = 3g, Final mass = 7g. Change in mass = $7 - 3 = 4$g.

Step7: Calculate Percent Change for Solution C

$\frac{4}{3} \times 100\% \approx 133.33\%$ (mass gain, water moved in, hypotonic solution).

Filled Table (Rows: Change in Mass, Percent Change, Type of Solution):

Solution	Change in Mass (g)	Percent Change	Type of Solution
B	-2	≈ -66.67%	Hypertonic
C	4	≈ 133.33%	Hypotonic

(Note: If the question was to fill the table, this is the completed version. If specific values for a column were needed, extract accordingly.)