Question

cw 1.2
period 3
find the length indicated.

1. ( g \bullet , ? , \bullet h , 11 , \bullet i ) (total ( 15 ))
2. ( c \bullet , ? , \bullet b , 7 , \bullet a ) (total ( 19 ))
3. ( q \bullet , ? , \bullet r , 5 , \bullet s ) (total ( 16 ))
4. ( i \bullet , ? , \bullet h , 1 , \bullet g ) (total ( 13 ))

solve for ( x ).

1. ( a \bullet , x+12 , \bullet b , x+6 , \bullet c ) (total ( 12 ))
2. ( c \bullet , x+15 , \bullet b , x+8 , \bullet a ) (total ( 15 ))
3. ( j \bullet , x-2 , \bullet k , 11 , \bullet l ) (total ( 3x-3 ))
4. ( g , 6 , \bullet h , x+3 , \bullet i , 2x-10 , \bullet j ) (total ( 26 ))

find the length indicated.

1. find ( ef ): ( d \bullet , 4 , \bullet e , 4x-1 , \bullet f ) (total ( 5x ))
2. find ( eg ): ( e \bullet , x+5 , \bullet f , 9 , \bullet g ) (total ( 4x-1 ))

Explanation:

Problem 1: Find the length indicated (G to H)

Step1: Use segment addition postulate.

The total length \( GI = 15 \), and \( HI = 11 \). Let \( GH = x \). Then \( x + 11 = 15 \).

Step2: Solve for \( x \).

Subtract 11 from both sides: \( x = 15 - 11 = 4 \).

Step1: Use segment addition postulate.

The total length \( CA = 19 \), and \( BA = 7 \). Let \( CB = x \). Then \( x + 7 = 19 \).

Step2: Solve for \( x \).

Subtract 7 from both sides: \( x = 19 - 7 = 12 \).

Step1: Use segment addition postulate.

The total length \( QS = 16 \), and \( RS = 5 \). Let \( QR = x \). Then \( x + 5 = 16 \).

Step2: Solve for \( x \).

Subtract 5 from both sides: \( x = 16 - 5 = 11 \).

Answer:

4

Problem 2: Find the length indicated (C to B)