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if the current in a resistive circuit is 24 ma and the applied voltage …

Question

if the current in a resistive circuit is 24 ma and the applied voltage is 48 v, what is the resistance?

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is \( V = IR \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance. We need to solve for \( R \), so rearrange the formula to \( R=\frac{V}{I} \).

Step2: Convert current to amps

The current \( I = 24\space mA \). Since \( 1\space mA=10^{- 3}\space A \), then \( I = 24\times10^{-3}\space A=0.024\space A \).

Step3: Substitute values into the formula

We know \( V = 48\space V \) and \( I = 0.024\space A \). Substitute into \( R=\frac{V}{I} \):
\( R=\frac{48}{0.024} \)

Step4: Calculate the resistance

\( \frac{48}{0.024}=2000\space\Omega \)

Answer:

The resistance is \( 2000\space\Omega \) (or \( 2\space k\Omega \))