Question

a crane lifts a load of steel that weighs 105 n a distance of 100 m. it takes 5 minutes to complete the task. how much work is done by the crane? how much power does the crane produce?

Explanation:

Step1: Calculate Work Done

Work \( W \) is calculated as force \( F \) times distance \( d \), \( W = F \times d \). Here, \( F = 105\,\text{N} \), \( d = 100\,\text{m} \).
\( W = 105 \times 100 = 10500\,\text{J} \) (Joules).

Step2: Convert Time to Seconds

Time \( t = 5\,\text{minutes} \). Since \( 1\,\text{min} = 60\,\text{s} \), \( t = 5 \times 60 = 300\,\text{s} \).

Step3: Calculate Power

Power \( P \) is work over time, \( P = \frac{W}{t} \). Substitute \( W = 10500\,\text{J} \), \( t = 300\,\text{s} \).
\( P = \frac{10500}{300} = 35\,\text{W} \) (Watts).

Answer:

Work done: \( 10500\,\text{J} \), Power: \( 35\,\text{W} \)