Question

consider the following series of arithmetic expressions.
int a = -1;
int b = 6;
int c = 8;
a -= 5 * a - 12 / b;
b += 2 - c % a;
c = c / 2 % (a % 4);
system.out.println(a);
system.out.println(b);
system.out.println(c);
what is the output produced by this code?

Explanation:

Step1: Calculate the new value of a

The statement a -= 5 a - 12 / b is equivalent to a = a-(5 a - 12 / b).
Substitute a=-1 and b = 6 into the formula:

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Step2: Calculate the new value of b

The statement b += 2 - c % a is equivalent to b=b+(2 - c % a).
Substitute b = 6, c = 8, and a = 6 into the formula. First, calculate c%a=8\%6 = 2.
Then \(b=6+(2 - 2)=6\)

Step3: Calculate the new value of c

The statement c = c / 2 % (a % 4) is equivalent to first calculate \(c/2=8/2 = 4\), then calculate \(a\%4=6\%4 = 2\).
Finally \(c = 4\%2=0\)

Answer:

The output is \(a = 6\), \(b = 6\), \(c = 0\)