completely factor the expression by grouping, if possible.

\d^2 + 6d + 4d + 24\

Question

completely factor the expression by grouping, if possible.

\d^2 + 6d + 4d + 24\

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Factoring by Grouping", "Greatest Common Factor" ], "new_concepts": [], "current_concepts": [ "Factoring by Grouping", "Greatest Common Factor" ] } ## Group the terms into pairs Using the *Factoring by Grouping* knowledge point $$ (d^2 + 6d) + (4d + 24) $$ ## Factor out the greatest common factor from each group Using the *Greatest Common Factor* knowledge point $$ \begin{aligned} &d^2 + 6d = d(d + 6)\ &4d + 24 = 4(d + 6) \end{aligned} $$ ## Factor out the common binomial factor Using the *Factoring by Grouping* knowledge point $$ d(d + 6) + 4(d + 6) = (d + 6)(d + 4) $$ Completely factor the expression by grouping, if possible. $$d^2 + 6d + 4d + 24$$ $(d + 6)(d + 4)$ { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Factoring by Grouping" ] }

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QUESTION IMAGE

Question

Explanation:

Group the terms into pairs

Factor out the greatest common factor from each group

Factor out the common binomial factor

Answer: