QUESTION IMAGE
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Question
complete the table.
$f(b)=|-5b|$
| $b$ | $f(b)$ |
|---|---|
| $-1$ | |
| $0$ | |
| $1$ |
Step1: Substitute b=-2
$f(-2) = |-5\times(-2)| = |10| = 10$
Step2: Substitute b=-1
$f(-1) = |-5\times(-1)| = |5| = 5$
Step3: Substitute b=0
$f(0) = |-5\times0| = |0| = 0$
Step4: Substitute b=1
$f(1) = |-5\times1| = |-5| = 5$
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| $b$ | $f(b)$ |
|---|---|
| -1 | 5 |
| 0 | 0 |
| 1 | 5 |