Question

complete the table.

\\f(a) = a^2 - 5\\

\

$$\begin{array}{|c|c|} \\hline a & f(a) \\\\ \\hline -5 & \\\\ \\hline -3 & \\\\ \\hline -1 & \\\\ \\hline 1 & \\\\ \\hline \\end{array}$$

Explanation:

Evaluate the function at \(a = -5\)

$$ f(-5) = (-5)^2 - 5 = 25 - 5 = 20 $$

Evaluate the function at \(a = -3\)

$$ f(-3) = (-3)^2 - 5 = 9 - 5 = 4 $$

Evaluate the function at \(a = -1\) and \(a = 1\)

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Answer:

\(a\)	\(f(a)\)
\(-3\)	\(4\)
\(-1\)	\(-4\)
\(1\)	\(-4\)