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Question
comparing ecosystems: calculate the diversity index of each ecosystem below using the equation for simpson’s diversity index.
ecosystem a:
| population | n (# of individuals) |
|---|---|
| marabou stork | |
| african elephant | |
| nile crocodile |
what is n?
calculate the biodiversity index of ecosystem a. show your work.
ecosystem b:
| population | n (# of individuals) |
|---|---|
| marabou stork | |
| african elephant | |
| nile crocodile |
what is n?
calculate the biodiversity index of ecosystem b. show your work.
Step1: Count individuals in Ecosystem A
- Acacia trees: 3 (from the image: three trees)
- Marabou stork: 2 (two storks)
- African elephant: 3 (three elephants)
- Nile crocodile: 2 (two crocodiles)
- Total \( N = 3 + 2 + 3 + 2 = 13 \)
- Simpson’s Diversity Index formula: \( D = 1 - \frac{\sum n(n - 1)}{N(N - 1)} \)
- Calculate \( \sum n(n - 1) \):
- Acacia: \( 3(3 - 1) = 6 \)
- Stork: \( 2(2 - 1) = 2 \)
- Elephant: \( 3(3 - 1) = 6 \)
- Crocodile: \( 2(2 - 1) = 2 \)
- Sum: \( 6 + 2 + 6 + 2 = 16 \)
- \( N(N - 1) = 13(13 - 1) = 156 \)
- \( D = 1 - \frac{16}{156} = 1 - \frac{4}{39} = \frac{35}{39} \approx 0.897 \)
Step2: Count individuals in Ecosystem B
- Acacia trees: 1 (one tree)
- Marabou stork: 2 (two storks)
- African elephant: 6 (six elephants)
- Nile crocodile: 1 (one crocodile)
- Total \( N = 1 + 2 + 6 + 1 = 10 \)
- Calculate \( \sum n(n - 1) \):
- Acacia: \( 1(1 - 1) = 0 \)
- Stork: \( 2(2 - 1) = 2 \)
- Elephant: \( 6(6 - 1) = 30 \)
- Crocodile: \( 1(1 - 1) = 0 \)
- Sum: \( 0 + 2 + 30 + 0 = 32 \)
- \( N(N - 1) = 10(10 - 1) = 90 \)
- \( D = 1 - \frac{32}{90} = 1 - \frac{16}{45} = \frac{29}{45} \approx 0.644 \)
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- Ecosystem A: \( N = 13 \), Diversity Index \( \approx 0.897 \)
- Ecosystem B: \( N = 10 \), Diversity Index \( \approx 0.644 \)