Question

1. compare suppose the secondary coil has 100 loops and the primary coil has 200. what is the secondary coil voltage compared to the primary coil voltage?

Explanation:

Step1: Recall the transformer formula

The formula for a transformer is $\frac{V_s}{V_p}=\frac{N_s}{N_p}$, where $V_s$ is the secondary voltage, $V_p$ is the primary voltage, $N_s$ is the number of loops in the secondary coil, and $N_p$ is the number of loops in the primary coil.

Step2: Substitute the given values

Given $N_s = 100$ and $N_p=200$. Substituting into the formula: $\frac{V_s}{V_p}=\frac{100}{200}=\frac{1}{2}$.

Answer:

The secondary coil voltage is half of the primary coil voltage.