Question

1. colette is going camping in the snow. she carries all of her gear behind her on a sled. the sled has a mass of 34 kg. in order to maintain a constant velocity, colette must pull with a force of 26.7 n. what is the coefficient of kinetic friction between the sled and the snow?

μₖ = 0.14

μₖ = 0.08

μₖ = 0.79

μₖ = 0.05

Explanation:

Step1: Calculate the normal force

The normal force \(N\) on the sled is equal to its weight. Using the formula \(N = mg\), where \(m = 34\space kg\) and \(g=9.8\space m/s^{2}\).
\(N=34\times9.8 = 333.2\space N\)

Step2: Use the kinetic - friction formula

Since the sled moves at a constant velocity, the applied force \(F\) is equal to the kinetic - friction force \(F_{k}\). The formula for kinetic - friction force is \(F_{k}=\mu_{k}N\). We know \(F = 26.7\space N\) and \(N = 333.2\space N\). Rearranging the formula for \(\mu_{k}\), we get \(\mu_{k}=\frac{F_{k}}{N}\)
Substitute \(F_{k}=26.7\space N\) and \(N = 333.2\space N\) into the formula: \(\mu_{k}=\frac{26.7}{333.2}\approx0.08\)

Answer:

\(\mu_{k}=0.08\) (the second option)