Question

in the circuit below, 3 amperes of current passes through the light bulb. the resistance of the light bulb is 1.5 ohms. what is the voltage of the battery? 1.5ω? i = 3a select one: a. 3 volts b. 6 volts c. 4.5 volts d 1.5 volts

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $V = I \times R$, where $V$ is voltage, $I$ is current, and $R$ is resistance.

Step2: Plug in the values

$I = 3\ \text{A}$, $R = 1.5\ \Omega$. Calculate $V = 3 \times 1.5$.

Step3: Compute the result

$3 \times 1.5 = 4.5$.

Answer:

c. 4.5 volts