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Question
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- the behavior of a gas can be approximated by the ideal gas law, $pv = nrt$. in this formula, $p$, $v$, and $t$ are the gas’s pressure, volume, and temperature; $n$ is the amount of the gas in moles; and $r$ is a constant. solve the formula for $t$.
- the formula for the volume of a right circular cone is shown. rewrite the formula so that it expresses the height $h$ in terms of the volume $v$ and base radius $r$.
image of a cone with height $h$, radius $r$, and formula $v = \frac{1}{3}\pi r^2 h$
- solve the literal equation $a(bx + c) = d$ for $x$. state any necessary restrictions on the letters representing constants in the equation. then use the solution of the literal equation to solve $-3(2x + 1) = 4$.
- alma is choosing a new smartphone and cellular service plan. let $p$ be the phone’s price in dollars, $m$ be the cost of the selected plan in dollars per month, and $c$ be alma’s total cost in dollars after time $t$, measured in months of service. write an equation that expresses $c$ in terms of $p$, $m$, and $t$. then solve your equation for $t$.
Problem 1
Step1: Start with the Ideal Gas Law formula \( PV = nRT \). We need to isolate \( T \).
To solve for \( T \), we divide both sides of the equation by \( nR \) (assuming \( n
eq0 \) and \( R
eq0 \), since \( n \) is the amount of gas in moles and \( R \) is a constant, these conditions are usually satisfied in the context of ideal gas law).
\[
\frac{PV}{nR}=\frac{nRT}{nR}
\]
Step2: Simplify the right - hand side.
The \( n \) and \( R \) in the numerator and denominator on the right - hand side cancel out, leaving us with:
\[
T = \frac{PV}{nR}
\]
Step1: Start with the volume formula of a right - circular cone \( V=\frac{1}{3}\pi r^{2}h \). We want to solve for \( h \).
First, multiply both sides of the equation by 3 to get rid of the fraction on the right - hand side.
\[
3V=\pi r^{2}h
\]
Step2: Isolate \( h \).
Divide both sides of the equation by \( \pi r^{2} \) (assuming \( r
eq0 \), because if \( r = 0 \), the cone degenerates to a line and the volume formula is not meaningful in the context of a non - degenerate cone).
\[
h=\frac{3V}{\pi r^{2}}
\]
Step1: Start with the equation \( a(bx + c)=d \). First, divide both sides by \( a \) (assuming \( a
eq0 \), because if \( a = 0 \), the left - hand side becomes 0, and if \( d
eq0 \), the equation has no solution; if \( d = 0 \), the equation becomes \( 0=0 \) for all \( x \) when \( a = 0 \)).
\[
bx + c=\frac{d}{a}
\]
Step2: Subtract \( c \) from both sides.
\[
bx=\frac{d}{a}-c=\frac{d - ac}{a}
\]
Step3: Divide both sides by \( b \) (assuming \( b
eq0 \), because if \( b = 0 \), the left - hand side becomes 0, and if \( \frac{d - ac}{a}
eq0 \), the equation has no solution; if \( \frac{d - ac}{a}=0 \), the equation becomes \( 0 = 0 \) for all \( x \) when \( b = 0 \)).
\[
x=\frac{d - ac}{ab}
\]
Now, use this solution to solve \( - 3(2x+1)=4 \). Here, \( a=-3 \), \( b = 2 \), \( c = 1 \), \( d = 4 \).
Substitute these values into the formula \( x=\frac{d - ac}{ab} \):
\[
x=\frac{4-(-3)\times1}{(-3)\times2}=\frac{4 + 3}{-6}=\frac{7}{-6}=-\frac{7}{6}
\]
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\( T=\frac{PV}{nR} \)