Question

calculating net force
what is the magnitude and direction (right or left) of the net force acting on the box?
$f_{n}=12n$
$f_{p}=15n$
$f_{f}=3n$
$f_{g}=12n$
n to the

Explanation:

Step1: Analyze vertical forces

The normal force \( F_N = 12\,\text{N} \) (upward) and gravitational force \( F_g = 12\,\text{N} \) (downward). Since they are equal in magnitude and opposite in direction, the net force in the vertical direction is \( F_{net, vertical} = 12 - 12 = 0\,\text{N} \).

Step2: Analyze horizontal forces

The applied force \( F_p = 15\,\text{N} \) (right) and friction force \( F_f = 3\,\text{N} \) (left). To find the net horizontal force, subtract the smaller force from the larger one: \( F_{net, horizontal} = 15 - 3 = 12\,\text{N} \). The direction is the same as the larger force, which is right.

Answer:

12 N to the right