Question

(a) calculate the momentum of a 2200 kg elephant charging a hunter at a speed of 7.50 m/s. kg·m/s (b) compare the elephants momentum with that of a 0.0400 kg bullet fired at a speed of 600 m/s. elephants momentum / bullets momentum = (c) what is the momentum in kilograms times meters per second of the 90.0 kg hunter running at 7.50 m/s after missing the elephant? kg·m/s

Explanation:

Step1: Calculate the elephant's momentum

The formula for momentum is \(p = mv\). For the elephant, \(m = 2200\space kg\) and \(v=7.50\space m/s\). So \(p_{elephant}=2200\times7.50\).

$$p_{elephant}=2200\times7.50 = 16500\space kg\cdot m/s$$

Step2: Calculate the bullet's momentum

For the bullet, \(m = 0.0400\space kg\) and \(v = 600\space m/s\). Using \(p=mv\), we have \(p_{bullet}=0.0400\times600\).

$$p_{bullet}=0.0400\times600=24\space kg\cdot m/s$$

Then find the ratio \(\frac{p_{elephant}}{p_{bullet}}=\frac{16500}{24}\)

$$ \frac{16500}{24}=687.5$$

Step3: Calculate the hunter's momentum

For the hunter, \(m = 90.0\space kg\) and \(v = 7.50\space m/s\). Using \(p = mv\), we get \(p_{hunter}=90.0\times7.50\)

$$p_{hunter}=90.0\times7.50 = 675\space kg\cdot m/s$$

Answer:

(a) \(16500\space kg\cdot m/s\)
(b) \(687.5\)
(c) \(675\space kg\cdot m/s\)