Question

calculate the eccentricity for the planet if the distance between foci is 5,000,000 km and the distance of the major axis is 299,000,000 km. (1 point) 0.0167 0.167 0.598 59.8

Explanation:

Step1: Recall the formula for eccentricity

The formula for the eccentricity \(e\) of an ellipse is \(e=\frac{c}{a}\), where \(c\) is the distance from the center to a focus (half of the distance between foci) and \(a\) is the semi - major axis (half of the major axis length).
Given that the distance between foci is \(d = 5000000\) km, so \(c=\frac{d}{2}=\frac{5000000}{2}=2500000\) km.
Given that the major axis length is \(l = 299000000\) km, so \(a=\frac{l}{2}=\frac{299000000}{2}=149500000\) km.

Step2: Calculate the eccentricity

Substitute \(c = 2500000\) and \(a=149500000\) into the formula \(e=\frac{c}{a}\).
\(e=\frac{2500000}{149500000}\approx0.0167\)

Answer:

0.0167