Question

a bucket of water experiencing a gravitational force of 525 n is pulled up from a water well. the net force in the y - direction is 45 n; therefore, the magnitude of the force of tension is n.

Explanation:

Step1: Identify forces and net force formula

The forces acting on the bucket are tension (\(T\)) upward and gravitational force (\(F_g = 525\,\text{N}\)) downward. The net force (\(F_{\text{net}}\)) in the \(y\)-direction is given by \(F_{\text{net}}=T - F_g\) (since tension is upward and gravity is downward, we take upward as positive).

Step2: Solve for tension

We know \(F_{\text{net}} = 45\,\text{N}\) and \(F_g = 525\,\text{N}\). Rearranging the formula \(F_{\text{net}}=T - F_g\) to solve for \(T\) gives \(T=F_{\text{net}}+F_g\). Substituting the values, we get \(T = 45\,\text{N}+ 525\,\text{N}\).

Step3: Calculate the tension

\(T=45 + 525=570\,\text{N}\).

Answer:

\(570\)