Question

1. brunhilda pushes on a box with a mass of 20 kilograms with a force of 35 newtons to the left. siegfried pushes on the opposite side of the box with a force of 25 newtons to the right. the box is sitting on the ground.

i. create a free body diagram (fbd) for the box
ii. calculate the net force in the x direction.
iii. calculate the acceleration of the box in the x direction.

Explanation:

Step1: Create Free Body Diagram (FBD)

• Draw a rectangle to represent the box.
• Draw an arrow pointing to the left labeled \( F_{Brunhilda}=35\ N \) (force applied by Brunhilda).
• Draw an arrow pointing to the right labeled \( F_{Siegfried}=25\ N \) (force applied by Siegfried).
• Draw an arrow pointing down labeled \( mg \) (weight, \( m = 20\ kg\), \( g=9.8\ m/s^{2}\)).
• Draw an arrow pointing up labeled \( N \) (normal force).

Step2: Calculate Net Force in x - direction

Let left be the negative direction and right be the positive direction.

$$
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$$

Step3: Calculate Acceleration in x - direction

Using Newton's second law \( F_{net,x}=ma_{x} \), where \( m = 20\ kg\) and \( F_{net,x}=-10\ N \)

$$
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$$

Answer:

i. Free body diagram as described above.
ii. The net force in the x - direction is \(-10\ N\).
iii. The acceleration of the box in the x - direction is \(-0.5\ m/s^{2}\).